In the given figure, AC = 37 cm, PC = 29 cm. The radius of the smaller circle is 20 cm, respectively. Find distance AB.

- 4
- 8
- 16
- 20

Option 3 : 16

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In ΔBPC,

⇒ PC^{2} = BP^{2} + BC^{2}

⇒ BC^{2} = 29^{2 }– 20^{2 }= 841 - 400 = 441

∴ BC = 21 cm

⇒ AB = AC – BC = 37 – 21 = 16 cm

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